The main challenge was understanding how to count subarrays with exactly k odd numbers instead of just finding a valid window. 🧩 Problem Breakdown Input: An integer array nums An integer k Output: ...
Solution SELECT DISTINCT l1.num AS ConsecutiveNums FROM Logs l1 JOIN Logs l2 ON l1.id = l2.id - 1 JOIN Logs l3 ON l2.id = l3.id - 1 WHERE l1.num = l2.num AND l2.num = l3.num; Key Concepts ->Self Joins ...
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